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Common mistakes

Why do I get the wrong answer?

Each of these is a common mistake in 2x+6=142x + 6 = 14 and similar equations. The fastest way to catch any of them: put your answer back into the equation and see whether both sides are equal.

Mistakes, and what to do instead

  • Mistake 1 · Why do I get x=10x = 10 in 2x+6=142x + 6 = 14?

    Why it happens
    You added 66 instead of removing it: 2x=202x = 20. Check: 2⋅10+6=262 \cdot 10 + 6 = 26, not 1414.
    What to do instead
    Subtract 66 from both sides: 2x=82x = 8, so x=4x = 4.
  • Mistake 2 · Why do I get x=1x = 1?

    Why it happens
    You divided only the 2x2x by 22, and the 66 stayed: x+6=7x + 6 = 7.
    What to do instead
    Remove the +6+ 6 first, then divide: 2x=82x = 8, x=4x = 4.
  • Mistake 3 · Why do I get x=8x = 8?

    Why it happens
    That’s 2x2x, not xx yet: one step was left.
    What to do instead
    Divide both sides by 22: x=4x = 4.
  • Mistake 4 · Why do I get 7x=127x = 12 in 5x+2=2x+145x + 2 = 2x + 14?

    Why it happens
    You “moved” the 2x2x across with the wrong sign.
    What to do instead
    Subtract 2x2x from both sides: 3x+2=143x + 2 = 14, 3x=123x = 12, x=4x = 4.
  • Mistake 5 · Why do I get x=143x = \frac{14}{3} in 3(x−2)=123(x - 2) = 12?

    Why it happens
    You multiplied only the xx by 33: 3x−2=123x - 2 = 12.
    What to do instead
    Multiply every term inside the brackets by 33 (the distributive law): 3x−6=123x - 6 = 12, 3x=183x = 18, x=6x = 6.

A check you can always do alone

Put the answer back into the original equation. If both sides are equal, it’s right: 2⋅4+6=142 \cdot 4 + 6 = 14. If they are not, look for the step where the two sides stopped being equal.

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